The naming of (1-ethyl-1H-pyrazol-4-yl) methanol is relatively straightforward, but we can further analyze its structure and confirm the accuracy of its naming according to the systematic nomenclature of organic compounds.

Firstly, we identified that the main skeleton of the compound is a pyrazole ring, which is a five membered heterocyclic ring containing two nitrogen atoms. One nitrogen atom participates in the formation of the ring as a heteroatom, while the other nitrogen atom carries a hydrogen atom (i.e. 1H pyrazole), indicating that there is a hydrogen atom attached to the nitrogen atom.

Next, we note that there is a substituent attached to the 4th position of the pyrazole ring, which is a methanol group (i.e. - CH2 OH). In naming, this substituent is described as a part of "(1-ethyl-1H-pyrazol-4-yl)", but in reality it is directly attached to the 4th position of the pyrazole ring, so a more accurate description would be "4-methoxy".

However, since the entire group (including the pyrazole ring and the ethanol group) is considered as a whole, and the ethanol group is attached to a specific position on the pyrazole ring, the expression "(1-ethyl-1H-pyrazol-4-yl)" is retained in the naming to emphasize that the ethanol group is attached to the pyrazole ring at this specific position.

Finally, we note that the 1st position of the pyrazole ring (i.e. the carbon atom that is not directly connected to either nitrogen atom) is connected to an ethyl group (- CH2 CH3). This ethyl group is clearly reflected in the naming, namely "1-ethyl".

In summary, the naming of (1-ethyl-1H-pyrazol-4-yl) methanol is accurate as it describes a pyrazole ring with an ethyl group attached at position 1 and a methanol group attached at position 4. This compound can also be described as 4- (hydroxymethyl) -1-ethyl-1H-pyrazole, but usually the former is more common and intuitive.